w^2+60w-16000=0

Solution for w^2+60w-16000=0 equation:

w^2+60w-16000=0

a = 1; b = 60; c = -16000;
Δ = b2-4ac
Δ = 602-4·1·(-16000)
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{67600}=260$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-260}{2*1}=\frac{-320}{2}
=-160
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+260}{2*1}=\frac{200}{2}
=100
$